# 25x 2 10x 1

Click here 👆 to get an answer to your question ️ Factorise-25x^2-10x+1-36y^2 terwadshreya235 terwadshreya235 21.08.2017 Math Secondary School Factorise-25x^2-10x+1-36y^2 2 See answers phillipinestest phillipinestest Answer: By factorization of,we get ((5x-1) + 6y) ((5x-1) - 6y)

f (x) = 25x2 − 10x + 1 f ( x) = 25 x 2 - 10 x + 1. The discriminant of a quadratic is the expression inside the radical of the quadratic formula. b2 − 4(ac) b 2 - 4 ( a c) Substitute in the values of a a, b b, and c c. (−10)2 −4(25⋅1) ( - 10) 2 - 4 ( 25 ⋅ 1) Evaluate the result to find the discriminant.

29.10.2020

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Show transcribed image text. Expert Answer 25x^2 + 10x + 1-----Notice that the 1st and the 3rd terms are perfect squares---The square roots are 5x and 1----The 2nd term is 2 times the product of those square roots: 2*5x*1 = 10x-----NOTE: A trinomial that meets those conditions is called a Perfect trinomial square.----Factoring a perfect trinomial square: EX: log(10 / 2) = log(10) - log(2) = 1 - 0.301 = 0.699. If there is an exponent in the argument of a logarithm, the exponent can be pulled out of the logarithm and multiplied. log b x y = y × log b x EX: log(2 6) = 6 × log(2) = 1.806.

## Feb 28, 2017 · Zeroes, or x-intercepts, are x = 4/5 and -6/5 When a math problem asks to find the "zeroes" of the equation, it is asking for the x-intercepts of the equation. In other words, you must set the equation equal to zero. Step 1: Set it equal to zero 0=25x^2+10x-24 Step 2: Move the equation to the left side by subtracting 25x^2+10x-24 You're left with: -25x^2-10x+24=0 Step 3: Factor! (-5x+4)(5x+6

E: Ans = Equation at the end of step 2 : 25x 2 - 10x - 1 = 0 Step 3 : Parabola, Finding the Vertex : 3.1 Find the Vertex of y = 25x 2-10x-1 Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . 2.1 Factoring 25x 2-10x+1 The first term is, 25x 2 its coefficient is 25 . The middle term is, -10x its coefficient is -10 .

### Jul 06, 2008

I was just wondering if somebody could help me factor the following problem: 16y ^2-25x^2+10x-1.

let us now solve the equation by Completing The Square and by using the Quadratic Formula. Parabola, Finding the Vertex : 4.1 Find the Vertex of y = 25x 2-10x+1 Parabolas have a highest or a lowest point called the Vertex . f (x) = 25x2 − 10x + 1 f (x) = 25 x 2 - 10 x + 1 The discriminant of a quadratic is the expression inside the radical of the quadratic formula. b2 − 4(ac) b 2 - 4 (a c) Substitute in the values of a a, b b, and c c.

PLEASE HELP Also, be careful when you write fractions: 1/x^2 ln(x) is `1/x^2 ln(x)`, and 1/(x^2 ln(x)) is `1/(x^2 ln(x))`. If you skip parentheses or a multiplication sign, type at least a whitespace, i.e. write sin x (or even better sin(x)) instead of sinx. Sometimes I see expressions like tan^2xsec^3x: this will be parsed as `tan^(2*3)(x sec(x))`.

Click here👆to get an answer to your question ️ Factorise : 25x^2 - 10x + 1 - 36y^2 Oct 14, 2009 · 25x^(2)-10x+1=0. x=(-b\ sqare root (b^(2)-4ac))/(2a) where ax^(2)+bx+c=0. a=25, b=-10, and c=1. b^(2)-4ac ((-10)^(2)-4(25)(1)) (((-10)(-10))-4(25)(1)) (((100))-4(25)(1)) For example, 2 3 = 8 ⇒ log 2 8 = 3 (the logarithm of 8 to base 2 is equal to 3, because 2 3 = 8). Similarly, log 2 64 = 6, because 2 6 = 64. Therefore, it is obvious that logarithm operation is an inverse one to exponentiation.

In general: ax 2 + bx + c = a(x - x 1)(x - x 2) , x 1 and x 2 are roots of equation ax 2 + bx + c = 0 , and x 12 = (-b ± √D)/2a , D = b 2 - 4ac . ~~~~~ 25x 2 - 10x + 1 = 0 D = (-10) 2 - 4 · 25 · 1 = 100 - 100 = 0 the equation has only one root (actually 2 roots with the same value) x 12 = -(-10)/(2 · 25) x 12 = 1/5 Graph f(x)=x^2-10x+25. Find the properties of the given parabola. Tap for more steps Rewrite the equation in vertex form.

Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework. 25x² - 10x + 1 → [5x - 1]²; set this Binomial equal to 0, and you get your x-intercept of [⅕, 0], which is also your vertex. Now, for your discriminant, you have to use all the values of c , b , and a to find it [b² - 4ac]: x2+25x-100 Final result : x2 + 25x - 100 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2+25x-100 The first term is, x2 its coefficient is 25x 2 - 10x + 1 = (5x) 2 - 2· 5x · 1 + 1 2 = (5x - 1) 2 .

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### 25x 2 - 10x + 1 = (5x) 2 - 2· 5x · 1 + 1 2 = (5x - 1) 2 . In general: ax 2 + bx + c = a(x - x 1)(x - x 2) , x 1 and x 2 are roots of equation ax 2 + bx + c = 0 , and x 12 = (-b ± √D)/2a , D = b 2 - 4ac . ~~~~~ 25x 2 - 10x + 1 = 0 D = (-10) 2 - 4 · 25 · 1 = 100 - 100 = 0 the equation has only one root (actually 2 roots with the same value) x 12 = -(-10)/(2 · 25) x 12 = 1/5

(-5x+4)(5x+6 Equation at the end of step 2 : 25x 2 - 10x - 1 = 0 Step 3 : Parabola, Finding the Vertex : 3.1 Find the Vertex of y = 25x 2-10x-1 Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . 2.1 Factoring 25x 2-10x+1 The first term is, 25x 2 its coefficient is 25 . The middle term is, -10x its coefficient is -10 .